1
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2
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- Branch
- Part of a circuit that can be simplified into two terminals
- Components between these two terminals
- Resistors, voltage sources, or other elements
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3
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- Complex circuits
- May be separated both series and/or parallel elements
- Other circuits
- Combinations which are neither series nor parallel
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4
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- To analyze a circuit
- Identify elements in series and elements in parallel
- In this circuit
- R2, R3, and R4 are in parallel
- This parallel combination
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5
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6
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- In this circuit
- R3 and R4 are in parallel
- Combination is in series with R2
- Entire combination is in parallel with R1
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7
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- Rules for analyzing series and parallel circuits still apply
- Same current occurs through all series elements
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8
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- Same voltage occurs across all parallel elements
- KVL and KCL apply for all circuits
- Whether they are series, parallel, or series-parallel
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9
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- Redraw complicated circuits showing the source at the left-hand side
- Label all nodes
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10
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- Develop a strategy
- Best to begin analysis with components most distant from the source
- Simplify recognizable combinations of components
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11
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- Determine equivalent resistance RT
- Solve for the total current
- Label polarities of voltage drops on all components
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12
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- Calculate how currents and voltages split between elements in a circuit
- Verify your answer by taking a different approach (when feasible)
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13
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- Combining R2 and R3 in parallel
- Circuit reduces to a series circuit
- Use Voltage Divider Rule to determine Vab and Vbc.
- Note that Vbc = V2 is the voltage across R2
and R3
- Calculate all currents from Ohm’s Law.
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14
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15
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- To find voltage Vab,
- Redraw circuit in simple form
- Original circuit
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16
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- Vab
- Determined by combination of voltages across R1 and R2 ,
or R3 and R4
- Use Voltage Divider Rule to find two voltages
- Use KVL to find Vab
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17
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18
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- To find currents in the circuit
- First redraw the circuit
- Move source branch all the way to left
- Reduce circuit to a series circuit
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19
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20
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- Voltages
- Use Ohm’s Law or Voltage Divider Rule
- Currents
- Use Ohm’s Law or Current Divider Rule
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21
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22
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- Circuit has Rx = 15 kW
- Determine Vab
- Redraw circuit as shown on slide
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23
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- Voltage Divider Rule
- Ground reference point
- Take at bottom of circuit
- Vab = 0.5 V
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24
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- Rx is a short circuit (0 W)
- Voltage Divider Rule
- VR2 = 10 V
- Vab = 8 V
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25
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- Rx is open
- Find VR1
- We know VR2 = 0 V
- Vab = –2 V
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26
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- Transistor
- Device that amplifies a signal
- Operating point of a transistor circuit
- Determined by a dc voltage source
- We will determine some dc voltages and currents
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27
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28
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- Apply KVL:
- VBB = RBIB + VBE + REIE
- Using IE = 100IB, we find IB = 14.3 mA.
- Other voltages and currents can be determined
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29
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- Example of variable resistor used as potentiometer
- Volume control on a receiver
- Moveable terminal is at uppermost position
- At the lowermost position
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30
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31
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- Vbc changes
- If load is added to circuit
- At upper position
- At the lower position
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